python-python3 undefined _ne__;返回与defined _eq相同的值__

我有一个班我的班在哪里__eq__定义如下：

def __eq__(self, other):
        try:
            other = MyClass(other)
        except Exception as e:
            raise ValueError(f"MyClass.__eq__ failed: {other} doesn't appear to be a valid MyClass type. \n", e )

        prefix_i1 = re.findall("[ab]" , self       )
        prefix_i2 = re.findall("[ab]" , other )
        if len( set( prefix_i1 + prefix_i2 ) ) > 1:
            return False    # ie: "a07" != "b07" BUT  "k07" == "b07"
        else:
            return self.num_string == other.num_string   # eg: "i3" == "i03"

self.num_string = "".join(filter(str.isdigit, self               )).zfill(2)

出乎意料的是，我得到了这样的结果：

> MyClass('b05') == MyClass('i05')
True
> MyClass('b05') != MyClass('i05')
True

我想__ne__默认情况下not __eq__ and defining it explicitly was discouraged since Python 3.

我做错了什么？